Program : Array as a member of a Structure

    #include <iostream.h>
    #include <conio.h>
    struct employee
    {
        char name[10] ;
        char address[15] ;
        long int telephone_numbers[5] ;
    } ;
    void main ( )
    {
        struct employee input ( ) ;
        struct employee e ;
        int i ;
        clrscr ( ) ;
        e = input ( ) ;
         cout<<"\n\nEmployee Personal Information displayed... \n";
         cout<<"\nName    :  "<<e.name ;
        cout<<"\nAddress : "<<e.address ;
        cout<<"\nTelephone Numbers : ";
        for ( i = 0; e.telephone_numbers[i] > 0 && i < 5; i++ )
        cout<<"\n"<<e.telephone_numbers[i] ;
        getch ( ) ;
    }
    struct employee input ( )
    {
        struct employee temp ;
        long int no;
        int i ;
        cout<<"Input the following -\n";
        cout<<"Name : ";
        cin>>temp.name ;

        cout<<"Address : ";
        cin>>temp.address;

        cout<<"Telephone Numbers :\n";
        cout<<"(terminate with -ve number,\n" ;
        cout<<"if want to enter less than 5 telephone numbers)\n";
        i = 0;
        cin>>no ;
 /*     User can enter either 5 differrent telephone numbers or less.
    If he enters less than 5 telephone numbers then he may     terminate by entering negative
    number */
        while ( no > 0 && i < 4 )
        {
            temp.telephone_numbers[i] = no ;
            i++ ;
            //scanf("%ld",&no) ;
            cin>>no;
        }
        temp.telephone_numbers[i] = no ;
        return ( temp ) ;
    }